The observer, abandoned by the rocket. |

*U*and a rocket flying past with 4-velocity

*V*. What does the observer measure as the ordinary three-velocity,

*v*, of the rocket? In special relativity the answer is straightforward. Work in inertial coordinates (globally not locally) such that the observer is in the rest frame and the rocket is moving along the x-axis. Then the four-velocity of the observer is

*U*= (1 , 0 , 0 , 0)

^{μ}*V*=(γ , γv , 0 , 0)

^{μ}*v*is the three-velocity and

γ = 1 / (√(1 -

so that*v*^{2}) )*v*= √(1 - γ

^{-2})

"

It is easy enough to understand the first and last equations but the two middle ones were not so easy.

His (2.51) itself starts

that seems to come out of nowhere and had me thinking.

It all ends well with the gloriously tensorial equation

which allows me to proceed to section 2.6 on An Expanding Universe!

His (2.51) itself starts

γ = -

"since *η*_{μν}U^{μ}V^{ν}*η*_{00 }= -1"that seems to come out of nowhere and had me thinking.

It all ends well with the gloriously tensorial equation

*v*= √(1 - (

*U*)

_{ν }V^{ν}^{2})

which allows me to proceed to section 2.6 on An Expanding Universe!

The answers, and suggestions for improvement (!), are in Commentary App A Mapping S2 and R3.pdf.

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