In section 2.1 on gravitational red shift he says, in the accelerating rockets:
and on the tower in a gravity field
Those are both straight forward.
He then reminds us of the Newtonian potential and that ag = ∇Φ.
He then gets
(2.7a) comes straight from (2.5) by integrating the acceleration over time to get Δv.
But I don't see why (2.7b) follows from (2.7a).
However from (2.6) we can get
Those are both straight forward.
He then reminds us of the Newtonian potential and that ag = ∇Φ.
He then gets
(2.7a) comes straight from (2.5) by integrating the acceleration over time to get Δv.
But I don't see why (2.7b) follows from (2.7a).
However from (2.6) we can get
I don't follow Carroll's logic but I can get the same answer!
Resources.
The above is also in Commentary 2.1 Red Shift.pdf
The above is also in Commentary 2.1 Red Shift.pdf
This needs a picture to make sense if you don't have the book
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